Show only domain from blacklist_email
Asked Modified Viewed 3,247 times
Hi folks.
How can I show only the domian name from the field $data['blacklist_email'] ?
I was thinking on something about:
- but I can't figure out how exactly Im doing that..
Anyone having some input ?
Regards,
Smokeman.
How can I show only the domian name from the field $data['blacklist_email'] ?
I was thinking on something about:
Code Download source
$domain = preg_replace($data['blacklist_email'],'^.*@');- but I can't figure out how exactly Im doing that..
Anyone having some input ?
Regards,
Smokeman.
answered
Try this:
http://php.net/manual/de/function.strstr.php
Code Download source
<?php
$email = 'name@example.com';
$domain = strstr($email, '@');
echo $domain; // result: @example.com
$user = strstr($email, '@', true); // since PHP 5.3.0
echo $user; // result: name
?>
http://php.net/manual/de/function.strstr.php
AFter some more reading/serching I found out that this does the job:
- but then an error showing up in the errorlog: Undefined offset: 1
I don't know for sure how to use the code you provided.. ?
Code Download source
$exp_domain = explode('@', $data['blacklist_email']);
$domain = $exp_domain[1];- but then an error showing up in the errorlog: Undefined offset: 1
I don't know for sure how to use the code you provided.. ?
answered
If you already have only domain instead of full e@mail (mail,com instead => some@mail,com) , this error appears.
You can check with:
count($exp_domain)// must be at least 2
, or
isset($exp_domain[1]) //must be true
You can check with:
count($exp_domain)// must be at least 2
, or
isset($exp_domain[1]) //must be true
answered
Code Download source
$exp_domain = explode('@', $data['blacklist_email']);
$domain = (isset($exp_domain[1]) ? $exp_domain[1] : "");Thx Polarfox & ronald85. That worked fine. :G
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